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Pragyanandha vs Carlson Tiebreaker: The title match of Chess World Cup 2023 has now reached a very exciting turn. The Indian is up against Grandmaster R Pragnanandha and world number one Magnus Carlsen in the final. The second classical game of the FIDE World Cup chess tournament on Wednesday also went to a tie-breaker after a draw and the winner will be decided today. Let us tell you that 3 players from this tournament were to qualify for the candidates tournament. Pragyanandha has qualified for the 2024 candidates tournament by entering the finals. A total of 8 players will participate in the Candidates Tournament and whoever wins this tournament will challenge China’s World Champion Ding Liren next year and the winner of that match will be called the next World Champion.
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Talking about the Pragyanand vs Carlson match, the first day of the match which started on Tuesday ended in a draw after over four hours of play and over 70 moves. After this, on Wednesday, the second game between the two lasted for an hour and a half and after 30 moves both players agreed on a draw. A tiebreaker will be played between the two players today i.e. on August 24. Let’s know what are the rules of this tiebreaker-
Pragnanand vs Carlson: What do the tiebreaker rules say?
After the two classical matches were drawn, the tiebreaker will now be played in a quick format. The first two rounds of 25 minutes each will be played with 10 seconds for each move from the first move. If this does not result, then the event of time will begin here.
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In case of no decision after 25 minutes, there will be two rounds of 10 minutes with 10 seconds for each move.
If this also fails, two games of 5 minutes each will be played and during this time 3 seconds will be given for each move instead of 10 seconds.
If there is no result here too, a 3 minute round will be played and each move will be 2 seconds. These rounds of 3 minutes each will be played until a winner is decided.